fix: 邮箱打码

apps/vocal.js

@@ -1,7 +1,7 @@
 import plugin from '../../../lib/plugins/plugin.js'
 import { SunoClient } from '../client/SunoClient.js'
 import { Config } from '../utils/config.js'
-import { downloadFile } from '../utils/common.js'
+import { downloadFile, maskEmail } from '../utils/common.js'
 import common from '../../../lib/common/common.js'
 
 export class Vocal extends plugin {
@@ -59,7 +59,9 @@ export class Vocal extends plugin {
         let client = new SunoClient({ sessToken: sess, clientToken })
         let { credit, email } = await client.queryCredit()
         logger.info({ credit, email })
-        msg += `用户${email}余额：${credit}\n`
+        msg += `用户: ${maskEmail(email)} 余额：${credit}\n`
+        msg += '-------------------\n'
+        msg += 'Notice：每首歌消耗5credit，每次生成2首歌'
       }
       await e.reply(msg)
       return true

utils/common.js

@@ -14,7 +14,7 @@ import { translate } from './translate.js'
 import uploadRecord from './uploadRecord.js'
 import Version from './version.js'
 import fetch, { FormData, fileFromSync } from 'node-fetch'
-import https from "https";
+import https from 'https'
 let pdfjsLib
 try {
   pdfjsLib = (await import('pdfjs-dist')).default
@@ -1261,3 +1261,52 @@ export async function extractContentFromFile (fileMsgElem, e) {
     return {}
   }
 }
+
+/**
+ * generated by ai
+ * @param email
+ * @returns {string}
+ */
+export function maskEmail (email) {
+  // 使用正则表达式匹配电子邮件地址的用户名和域名部分
+  const regex = /^([^@]+)@([^@]+)$/
+  const match = email.match(regex)
+
+  if (!match) {
+    throw new Error('Invalid email format')
+  }
+
+  // 获取用户名和域名
+  const username = match[1]
+  const domain = match[2]
+
+  // 对用户名部分进行部分打码
+  const maskedUsername = maskString(username)
+
+  // 对域名部分进行部分打码
+  const maskedDomain = maskString(domain)
+
+  // 构造新的电子邮件地址
+  const maskedEmail = maskedUsername + '@' + maskedDomain
+
+  return maskedEmail
+}
+
+/**
+ * generated by ai
+ * @param str
+ * @returns {*|string}
+ */
+function maskString (str) {
+  // 如果字符串长度小于等于2，直接返回原字符串
+  if (str.length <= 2) {
+    return str
+  }
+
+  // 取字符串的前三个字符和后三个字符，中间使用*代替
+  const firstThreeChars = str.substring(0, 3)
+  const lastThreeChars = str.substring(str.length - 3)
+  const maskedChars = '*'.repeat(str.length - 6)
+
+  return firstThreeChars + maskedChars + lastThreeChars
+}